10x^2-25x=125

Solution for 10x^2-25x=125 equation:

10x^2-25x=125

We move all terms to the left:

10x^2-25x-(125)=0

a = 10; b = -25; c = -125;
Δ = b2-4ac
Δ = -252-4·10·(-125)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-75}{2*10}=\frac{-50}{20}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+75}{2*10}=\frac{100}{20}
=5
$